Describe the issue:

import numpy as np
from typing import reveal_type

reveal_type(np.char.array('foo', unicode=False))

outputs

t.py:4: note: Revealed type is "numpy._core.defchararray.chararray[builtins.tuple[Any, ...], numpy.dtype[numpy.str_]]"

I'd have expected

t.py:4: note: Revealed type is "numpy._core.defchararray.chararray[builtins.tuple[Any, ...], numpy.dtype[numpy.bytes_]]"

I think the issue is

The default for unicode is None, not Literal[False]. It seems the idea is:

• unicode=True: return np.str_ type
• unicode=False: return np.bytes_ type
• unicode=None` (default): return either of the above, depending on the input

Spotted this while trying out https://github.com/MarcoGorelli/fix-overload-defaults

Reproduce the code example:

see above

Error message:

Python and NumPy Versions:

2.4.0.dev0+git20250714.cc92651
3.12.11 | packaged by conda-forge | (main, Jun 4 2025, 14:45:31) [GCC 13.3.0]

Type-checker version and settings:

mypy 1.16

Additional typing packages.

No response